First you need to make sure your system is up-do-date, for that you need to run

yum -y update

Download and install Composer by executing the following command:

curl -sS https://getcomposer.org/installer | php

Once the process completes, you can make the ‘composer.phar’ file executable by running the following command:

chmod +x composer.phar

Now use the following commands to make composer available globally for all users in your system, which can be used for all php applications on that system:

mv composer.phar /usr/local/bin/composer

You can also check the version of composer by running bellow command:

composer -V

And you are ready to go.

The post Installing Composer Globally on CentOS 7 appeared first on SideCode.

Just a small method that in WordPress I just add it (always) to the functions.php file, and in other php frameworks, add it as a general global helper function.

# The Method

/**
 *  Send debug code to the Javascript console (PHP Console Debugging)
 */
function debug_to_console($data, $tag = 'JHONNY') {
  if(is_array($data) || is_object($data)) {
     echo("<script>console.log('" . $tag. ": " .json_encode($data)."');</script>");
  } else {
     echo("<script>console.log('" . $tag. ": " .$data."');</script>");
  }
}

When added to functions.php It allows me to call the function anywhere in my theme,
The first argument $data – It’s the variable or array that I want to to see his state (the value).
The second argument $tag – It’s an optional tag you can add, so as it is printed out in the console, you can identify it better.

# On Small Projects

On small projects mostly there is no need to add the second argument, so as it is above, it will alwyas just print "JHONNY: " before the variable, so I know that this is printed out from this function.
So all you need to do is just give it the var you want to debug:

debug_to_console($tax_name)

It will look like this (In the browser console):

# On larger Projects

On larger projects, usually, I add the second argument with the class name or tepmplate page it belongs to with the var name, something like:

debug_to_console($image_url,"footer.php - imageUrl")

It will look like this (In the browser console):

The post Fast WordPress Debugging (Debug to console) appeared first on SideCode.